3.760 \(\int \frac {x^{5/2}}{(a+c x^4)^3} \, dx\)

Optimal. Leaf size=329 \[ \frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}+\frac {9 \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}+1\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}-\frac {9 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}+\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2} \]

[Out]

1/8*x^(7/2)/a/(c*x^4+a)^2+9/64*x^(7/2)/a^2/(c*x^4+a)+9/256*arctan(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(17/8)/c^(7
/8)-9/256*arctanh(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(17/8)/c^(7/8)+9/512*arctan(-1+c^(1/8)*2^(1/2)*x^(1/2)/(-a)
^(1/8))/(-a)^(17/8)/c^(7/8)*2^(1/2)+9/512*arctan(1+c^(1/8)*2^(1/2)*x^(1/2)/(-a)^(1/8))/(-a)^(17/8)/c^(7/8)*2^(
1/2)+9/1024*ln((-a)^(1/4)+c^(1/4)*x-(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(17/8)/c^(7/8)*2^(1/2)-9/1024*ln(
(-a)^(1/4)+c^(1/4)*x+(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(17/8)/c^(7/8)*2^(1/2)

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Rubi [A]  time = 0.31, antiderivative size = 329, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 12, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {290, 329, 301, 297, 1162, 617, 204, 1165, 628, 298, 205, 208} \[ \frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}+\frac {9 \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}+1\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}-\frac {9 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}+\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[x^(5/2)/(a + c*x^4)^3,x]

[Out]

x^(7/2)/(8*a*(a + c*x^4)^2) + (9*x^(7/2))/(64*a^2*(a + c*x^4)) - (9*ArcTan[1 - (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a)^
(1/8)])/(256*Sqrt[2]*(-a)^(17/8)*c^(7/8)) + (9*ArcTan[1 + (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*Sqrt[2]*
(-a)^(17/8)*c^(7/8)) + (9*ArcTan[(c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*(-a)^(17/8)*c^(7/8)) - (9*ArcTanh[(c^(1/8
)*Sqrt[x])/(-a)^(1/8)])/(256*(-a)^(17/8)*c^(7/8)) + (9*Log[(-a)^(1/4) - Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sqrt[x] + c
^(1/4)*x])/(512*Sqrt[2]*(-a)^(17/8)*c^(7/8)) - (9*Log[(-a)^(1/4) + Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sqrt[x] + c^(1/4
)*x])/(512*Sqrt[2]*(-a)^(17/8)*c^(7/8))

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 290

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(
a*c*n*(p + 1)), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; FreeQ[
{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 297

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 298

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(a/b),
2]]}, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &
&  !GtQ[a/b, 0]

Rule 301

Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(
a/b), 2]]}, Dist[s/(2*b), Int[x^(m - n/2)/(r + s*x^(n/2)), x], x] - Dist[s/(2*b), Int[x^(m - n/2)/(r - s*x^(n/
2)), x], x]] /; FreeQ[{a, b}, x] && IGtQ[n/4, 0] && IGtQ[m, 0] && LeQ[n/2, m] && LtQ[m, n] &&  !GtQ[a/b, 0]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {x^{5/2}}{\left (a+c x^4\right )^3} \, dx &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 \int \frac {x^{5/2}}{\left (a+c x^4\right )^2} \, dx}{16 a}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}+\frac {9 \int \frac {x^{5/2}}{a+c x^4} \, dx}{128 a^2}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}+\frac {9 \operatorname {Subst}\left (\int \frac {x^6}{a+c x^8} \, dx,x,\sqrt {x}\right )}{64 a^2}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}-\frac {9 \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-a}-\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{128 a^2 \sqrt {c}}+\frac {9 \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{128 a^2 \sqrt {c}}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}-\frac {9 \operatorname {Subst}\left (\int \frac {1}{\sqrt [4]{-a}-\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{256 a^2 c^{3/4}}+\frac {9 \operatorname {Subst}\left (\int \frac {1}{\sqrt [4]{-a}+\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{256 a^2 c^{3/4}}-\frac {9 \operatorname {Subst}\left (\int \frac {\sqrt [4]{-a}-\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{256 a^2 c^{3/4}}+\frac {9 \operatorname {Subst}\left (\int \frac {\sqrt [4]{-a}+\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{256 a^2 c^{3/4}}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}+\frac {9 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}-\frac {9 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}+\frac {9 \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{512 a^2 c}+\frac {9 \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{512 a^2 c}+\frac {9 \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}+2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}-2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}+\frac {9 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}-\frac {9 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}+\frac {9 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}\\ &=\frac {x^{7/2}}{8 a \left (a+c x^4\right )^2}+\frac {9 x^{7/2}}{64 a^2 \left (a+c x^4\right )}-\frac {9 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{17/8} c^{7/8}}+\frac {9 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}-\frac {9 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{17/8} c^{7/8}}+\frac {9 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}-\frac {9 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{17/8} c^{7/8}}\\ \end {align*}

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Mathematica [C]  time = 0.01, size = 29, normalized size = 0.09 \[ \frac {2 x^{7/2} \, _2F_1\left (\frac {7}{8},3;\frac {15}{8};-\frac {c x^4}{a}\right )}{7 a^3} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(5/2)/(a + c*x^4)^3,x]

[Out]

(2*x^(7/2)*Hypergeometric2F1[7/8, 3, 15/8, -((c*x^4)/a)])/(7*a^3)

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fricas [B]  time = 0.57, size = 672, normalized size = 2.04 \[ -\frac {36 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {2} \sqrt {\sqrt {2} a^{15} c^{6} \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {7}{8}} - a^{13} c^{5} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {3}{4}} + x} a^{2} c \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} - \sqrt {2} a^{2} c \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} + 1\right ) + 36 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {2} \sqrt {-\sqrt {2} a^{15} c^{6} \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {7}{8}} - a^{13} c^{5} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {3}{4}} + x} a^{2} c \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} - \sqrt {2} a^{2} c \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} - 1\right ) - 9 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \log \left (\sqrt {2} a^{15} c^{6} \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {7}{8}} - a^{13} c^{5} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {3}{4}} + x\right ) + 9 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \log \left (-\sqrt {2} a^{15} c^{6} \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {7}{8}} - a^{13} c^{5} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {3}{4}} + x\right ) + 72 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {-a^{13} c^{5} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {3}{4}} + x} a^{2} c \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} - a^{2} c \sqrt {x} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}}\right ) - 18 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \log \left (a^{15} c^{6} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {7}{8}} + \sqrt {x}\right ) + 18 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {1}{8}} \log \left (-a^{15} c^{6} \left (-\frac {1}{a^{17} c^{7}}\right )^{\frac {7}{8}} + \sqrt {x}\right ) - 16 \, {\left (9 \, c x^{7} + 17 \, a x^{3}\right )} \sqrt {x}}{1024 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)/(c*x^4+a)^3,x, algorithm="fricas")

[Out]

-1/1024*(36*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^17*c^7))^(1/8)*arctan(sqrt(2)*sqrt(sqrt(2)*a^15*c
^6*sqrt(x)*(-1/(a^17*c^7))^(7/8) - a^13*c^5*(-1/(a^17*c^7))^(3/4) + x)*a^2*c*(-1/(a^17*c^7))^(1/8) - sqrt(2)*a
^2*c*sqrt(x)*(-1/(a^17*c^7))^(1/8) + 1) + 36*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^17*c^7))^(1/8)*a
rctan(sqrt(2)*sqrt(-sqrt(2)*a^15*c^6*sqrt(x)*(-1/(a^17*c^7))^(7/8) - a^13*c^5*(-1/(a^17*c^7))^(3/4) + x)*a^2*c
*(-1/(a^17*c^7))^(1/8) - sqrt(2)*a^2*c*sqrt(x)*(-1/(a^17*c^7))^(1/8) - 1) - 9*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x
^4 + a^4)*(-1/(a^17*c^7))^(1/8)*log(sqrt(2)*a^15*c^6*sqrt(x)*(-1/(a^17*c^7))^(7/8) - a^13*c^5*(-1/(a^17*c^7))^
(3/4) + x) + 9*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^17*c^7))^(1/8)*log(-sqrt(2)*a^15*c^6*sqrt(x)*(
-1/(a^17*c^7))^(7/8) - a^13*c^5*(-1/(a^17*c^7))^(3/4) + x) + 72*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^17*c^
7))^(1/8)*arctan(sqrt(-a^13*c^5*(-1/(a^17*c^7))^(3/4) + x)*a^2*c*(-1/(a^17*c^7))^(1/8) - a^2*c*sqrt(x)*(-1/(a^
17*c^7))^(1/8)) - 18*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^17*c^7))^(1/8)*log(a^15*c^6*(-1/(a^17*c^7))^(7/8
) + sqrt(x)) + 18*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^17*c^7))^(1/8)*log(-a^15*c^6*(-1/(a^17*c^7))^(7/8)
+ sqrt(x)) - 16*(9*c*x^7 + 17*a*x^3)*sqrt(x))/(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)

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giac [B]  time = 0.86, size = 472, normalized size = 1.43 \[ \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (-\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} + \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \arctan \left (-\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} - \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (-\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} - \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} + \frac {9 \, \left (\frac {a}{c}\right )^{\frac {7}{8}} \log \left (-\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} + \frac {9 \, c x^{\frac {15}{2}} + 17 \, a x^{\frac {7}{2}}}{64 \, {\left (c x^{4} + a\right )}^{2} a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)/(c*x^4+a)^3,x, algorithm="giac")

[Out]

9/256*(a/c)^(7/8)*arctan((sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + 2*sqrt(x))/(sqrt(sqrt(2) + 2)*(a/c)^(1/8)))/(a^3*sq
rt(-2*sqrt(2) + 4)) + 9/256*(a/c)^(7/8)*arctan(-(sqrt(-sqrt(2) + 2)*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(sqrt(2) + 2
)*(a/c)^(1/8)))/(a^3*sqrt(-2*sqrt(2) + 4)) + 9/256*(a/c)^(7/8)*arctan((sqrt(sqrt(2) + 2)*(a/c)^(1/8) + 2*sqrt(
x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a^3*sqrt(2*sqrt(2) + 4)) + 9/256*(a/c)^(7/8)*arctan(-(sqrt(sqrt(2) + 2)
*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a^3*sqrt(2*sqrt(2) + 4)) - 9/512*(a/c)^(7/8)*log(
sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(-2*sqrt(2) + 4)) + 9/512*(a/c)^(7/8)*log(-s
qrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(-2*sqrt(2) + 4)) - 9/512*(a/c)^(7/8)*log(sqr
t(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(2*sqrt(2) + 4)) + 9/512*(a/c)^(7/8)*log(-sqrt
(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(2*sqrt(2) + 4)) + 1/64*(9*c*x^(15/2) + 17*a*x^
(7/2))/((c*x^4 + a)^2*a^2)

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maple [C]  time = 0.02, size = 62, normalized size = 0.19 \[ \frac {9 \ln \left (-\RootOf \left (c \,\textit {\_Z}^{8}+a \right )+\sqrt {x}\right )}{512 a^{2} c \RootOf \left (c \,\textit {\_Z}^{8}+a \right )}+\frac {\frac {9 c \,x^{\frac {15}{2}}}{64 a^{2}}+\frac {17 x^{\frac {7}{2}}}{64 a}}{\left (c \,x^{4}+a \right )^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(5/2)/(c*x^4+a)^3,x)

[Out]

2*(17/128*x^(7/2)/a+9/128/a^2*c*x^(15/2))/(c*x^4+a)^2+9/512/a^2/c*sum(1/_R*ln(-_R+x^(1/2)),_R=RootOf(_Z^8*c+a)
)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {9 \, c x^{\frac {15}{2}} + 17 \, a x^{\frac {7}{2}}}{64 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )}} + 9 \, \int \frac {x^{\frac {5}{2}}}{128 \, {\left (a^{2} c x^{4} + a^{3}\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)/(c*x^4+a)^3,x, algorithm="maxima")

[Out]

1/64*(9*c*x^(15/2) + 17*a*x^(7/2))/(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4) + 9*integrate(1/128*x^(5/2)/(a^2*c*x^4 +
a^3), x)

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mupad [B]  time = 1.10, size = 157, normalized size = 0.48 \[ \frac {\frac {17\,x^{7/2}}{64\,a}+\frac {9\,c\,x^{15/2}}{64\,a^2}}{a^2+2\,a\,c\,x^4+c^2\,x^8}+\frac {9\,\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}}{{\left (-a\right )}^{1/8}}\right )}{256\,{\left (-a\right )}^{17/8}\,c^{7/8}}+\frac {\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}\,1{}\mathrm {i}}{{\left (-a\right )}^{1/8}}\right )\,9{}\mathrm {i}}{256\,{\left (-a\right )}^{17/8}\,c^{7/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (\frac {9}{512}-\frac {9}{512}{}\mathrm {i}\right )}{{\left (-a\right )}^{17/8}\,c^{7/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (\frac {9}{512}+\frac {9}{512}{}\mathrm {i}\right )}{{\left (-a\right )}^{17/8}\,c^{7/8}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(5/2)/(a + c*x^4)^3,x)

[Out]

((17*x^(7/2))/(64*a) + (9*c*x^(15/2))/(64*a^2))/(a^2 + c^2*x^8 + 2*a*c*x^4) + (9*atan((c^(1/8)*x^(1/2))/(-a)^(
1/8)))/(256*(-a)^(17/8)*c^(7/8)) + (atan((c^(1/8)*x^(1/2)*1i)/(-a)^(1/8))*9i)/(256*(-a)^(17/8)*c^(7/8)) + (2^(
1/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 - 1i/2))/(-a)^(1/8))*(9/512 - 9i/512))/((-a)^(17/8)*c^(7/8)) + (2^(1/2
)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 + 1i/2))/(-a)^(1/8))*(9/512 + 9i/512))/((-a)^(17/8)*c^(7/8))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(5/2)/(c*x**4+a)**3,x)

[Out]

Timed out

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